How do you divide $\frac{- 3 x^{4} - 4 x^{2} + 2 x + 15}{x^{2} - x + 4}$ $(-3x^4-4x^2+2x+15)/(x^2-x+4)$ ?

Question

How do you divide $\frac{- 3 x^{4} - 4 x^{2} + 2 x + 15}{x^{2} - x + 4}$ $(-3x^4-4x^2+2x+15)/(x^2-x+4)$ ?

1 Answer

Impact of this question

1773 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-13T19:13:19

$- 3 x^{2} - 3 x - 3 + \frac{7 x + 27}{x^{2} - x + 4}$ $-3x^2-3x-3+(7x+27)/(x^2-x+4)$

Explanation:

$\frac{- 3 x^{4} - 4 x^{2} + 2 x + 15}{x^{2} - x + 4}$ $(-3x^4-4x^2+2x+15)/(x^2-x+4)$

$color(white)(....)color(white)(.............)-3x^2-3x-3$
$x^2-x+4|overline(-3x^4+"00"-4x^2+2x+15)$
$color(white)(...................)ul(-3x^4+3x^3-4x^2)$
$color(white)(......................)-3x^3+"00"+2x$
$color(white)(........................)ul(-3x^3+3x^2-12x)$
$color(white)(..................................)-3x^2+10x+15$
$color(white)(....................................)ul(-3x^2+3x-12)$
$color(white)(................................................)7x+27$

$(-3x^4-4x^2+2x+15)/(x^2-x+4) = -3x^2-3x-3+(7x+27)/(x^2-x+4)$

Science

Math

Humanities

... and beyond

How do you divide $\frac{- 3 x^{4} - 4 x^{2} + 2 x + 15}{x^{2} - x + 4}$ $(-3x^4-4x^2+2x+15)/(x^2-x+4)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide (-3x^4-4x^2+2x+15)/(x^2-x+4)−3x4−4x2+2x+15x2−x+4(-3x^4-4x^2+2x+15)/(x^2-x+4)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $\frac{- 3 x^{4} - 4 x^{2} + 2 x + 15}{x^{2} - x + 4}$ $(-3x^4-4x^2+2x+15)/(x^2-x+4)$ ?