How do you divide $(3x^4+9x^3-2x^2+2x-7)/(x-2)$ ?

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How do you divide $(3x^4+9x^3-2x^2+2x-7)/(x-2)$ ?

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Answer 1 · 2017-06-28T11:46:59

The remainder is $=109$ and the quotient is $=3x^3+15x^2+28x+58$

Explanation:

Let's perform the synthetic division

$color(white)(aaaa)$ $2$ $color(white)(aaaa)$ $|$ $color(white)(aaaa)$ $3$ $color(white)(aaaa)$ $9$ $color(white)(aaaaa)$ $-2$ $color(white)(aaaa)$ $2$ $color(white)(aaaaa)$ $-7$
$color(white)(aaaaaaaaaaaa)$ _________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $color(white)(aaa)$ $6$ $color(white)(aaaaaa)$ $30$ $color(white)(aaa)$ $56$ $color(white)(aaaaa)$ $116$
$color(white)(aaaaaaaaaaaa)$ ________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaa)$ $3$ $color(white)(aaa)$ $15$ $color(white)(aaaaa)$ $28$ $color(white)(aaa)$ $58$ $color(white)(aaaaa)$ $color(red)(109)$

The remainder is $=109$ and the quotient is $=3x^3+15x^2+28x+58$

Therefore,

$(3x^4+9x^3-2x^2+2x-7)/(x-2)=3x^3+15x^2+28x+58+(109)/(x-2)$

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How do you divide $(3x^4+9x^3-2x^2+2x-7)/(x-2)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you divide (3x^4+9x^3-2x^2+2x-7)/(x-2) (3x^4+9x^3-2x^2+2x-7)/(x-2) ?

1 Answer

Explanation:

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How do you divide $(3x^4+9x^3-2x^2+2x-7)/(x-2)$ ?