How do you divide (4-2i)/(3+7i)?

1 Answer
Jun 18, 2016

-1/29-17/29*i

Explanation:

you can multiply numerator and denominator by the expression

3-7i

((4-2i)(3-7i))/((3+7i)(3-7i))

and, by symplifying:

(12-28i-6i+14i^2)/(9-49i^2)

let's substitute i^2=-1 and sum similar terms:

(12-34i-14)/(9+49)

(-2-34i)/58

or

-2/58-(34/58)i

that's

-1/29-17/29*i