How do you divide (-4x^3-x^2+3x-4)/(x-3) −4x3−x2+3x−4x−3?

I changed (-4^3) rarr (-4x^3)(−43)→(−4x3). Sorry if this is not what was intended, but it seemed more likely.

1 Answer
Tony B
Jul 5, 2016

-4x^2-13x-36-112/(x-3)−4x2−13x−36−112x−3

Explanation:

" "-4x^3-x^2+3x-4 −4x3−x2+3x−4
color(magenta)(-4x^2)(x-3) ->ul( -4x^3+12x^2) larr" Subtract"
" "color(white)(..)0-13x^2+3x-4
color(magenta)(-13x)(x-3)->" "ul(color(white)(..)-13x^2+39x)" "larr" Subtract"
" "0color(white)(..)-36x-4
color(magenta)(-36)(x-3)->" "color(white)(..)ul(-36x+108)" "larr" Subtract"
" "0color(white)(..)color(magenta)(-112 larr" Remainder")

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

color(magenta)(-4x^2-13x-36-112/(x-3))

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