How do you divide #(4x^3-5x^2+9x-3)/(2x-3) #?

1 Answer
Johnson Z.
Dec 17, 2015

#y=((x^2+3)(4x-5)(3x-1))/(2x-3)#

Explanation:

#y=(4x^3-5x^2+9x-3)/(2x-3)#

Divide #2# terms at once by a common factor.
#y=(x^2(4x-5)+3(3x-1))/(2x-3)#

Rewrite the equation.
#y=((x^2+3)(4x-5)(3x-1))/(2x-3)#, #x!=3/2#

Since the equation cannot be simplified any further, the final answer is #y=((x^2+3)(4x-5)(3x-1))/(2x-3)# where #x!=3/2#.

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