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How do you divide $\frac{4 x^{3} + 7 x^{2} - 9 x + 15}{x + 1}$ $(4x^3+7x^2-9x+15)/(x+1)$ ?

1 Answer

Nov 14, 2017

$4 x^{2} + 3 x - 12 + \frac{27}{x + 1}$ $4x^2+3x-12+(27)/(x+1)$

Explanation:

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