How do you divide $\frac{4 x^{4} + 3 x^{3} + 3 x - 2}{x^{2} - 3}$ $(4x^4 + 3x^3 + 3x - 2) / ( x^2 - 3 )$ using polynomial long division?

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Answer 1 · 2018-07-20T21:31:51

$4 x^{2} + 3 x + 12 + \frac{12 x + 34}{x^{2} - 3}$ $4x^2 + 3x + 12 + (12x+34)/(x^2-3)$

To divide this, use long division:
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Hope this helps!

How do you divide (4x^4 + 3x^3 + 3x - 2) / ( x^2 - 3 ) 4x4+3x3+3x−2x2−3(4x^4 + 3x^3 + 3x - 2) / ( x^2 - 3 ) using polynomial long division?