How do you divide #(-5 - 3i)/(4i)#?
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"How do you name compounds containing polyatomic ions?"
1 Answer
Jun 17, 2018
Explanation:
#"we require the denominator to be real"#
#"this can be achieved by multiplying the numerator"#
#"and denominator by "i#
#[i^2=(sqrt(-1))^2=-1]#
#=(i(-5-3i))/(4i^2)#
#=(-5i+3)/(-4)#
#=(-5i)/(-4)+3/(-4)=-3/4+5/4ilarrcolor(red)"in standard form"#
