How do you divide (-5 - 3i)/(4i)−5−3i4i?
1 Answer
Jun 17, 2018
Explanation:
"we require the denominator to be real"we require the denominator to be real
"this can be achieved by multiplying the numerator"this can be achieved by multiplying the numerator
"and denominator by "iand denominator by i
[i^2=(sqrt(-1))^2=-1][i2=(√−1)2=−1]
=(i(-5-3i))/(4i^2)=i(−5−3i)4i2
=(-5i+3)/(-4)=−5i+3−4
=(-5i)/(-4)+3/(-4)=-3/4+5/4ilarrcolor(red)"in standard form"=−5i−4+3−4=−34+54i←in standard form
