How do you divide #(5-i)/(3+3i)#?

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Answer 1 · 2016-01-11T00:27:14

Multiply top and bottom by the conjugate of the denominator ...

#(5-i)/(3+3i)xx(3-3i)/(3-3i)=(12-18i)/(18)=2/3-i#

hope that helped

Answer 2 · 2016-01-11T00:28:33

Multiply the fraction by 1 (the conjugate of the denominator/the conjugate of the denominator)

#(5-i)/(3+3i)#*#(3-3i)/(3-3i)#=#(12-18i)/(9+9)#=#(1/18)(12-18i)#