How do you divide (6-6i)/(-4i)6−6i−4i?

1 Answer
Shwetank Mauria
Aug 21, 2016

(6-6i)/-4i=3/2+3/2i6−6i−4i=32+32i

Explanation:

In any question involving multiplication or division of complex number, one should always remember i^2=-1i2=−1.

In division the way is to rationalize the denominator. As we have only imaginary component in denominator, simply multiplying numerator annd denominator by ii should rationalize denominator.

Hence, (6-6i)/(-4i)6−6i−4i

= ((6-6i)×i)/(-4i×i)(6−6i)×i−4i×i

= (6i-6i^2)/(-4i^2)6i−6i2−4i2

= (6i+6)/(-4×-1)6i+6−4×−1

= (6i+6)/46i+64

= 6/4+(6i)/464+6i4

= 3/2+3/2i32+32i

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