Question

How do you divide `(-7+6i)/(10+5i)`?

Answer 1

`=-8/25+(19i)/25`

Explanation:

`(-7+6i)/(10+5i)=(-7+6i)/(5(2+i)) xx (2-i)/(2-i)`

`=((-7+6i)(2-i))/(5(2+i)(2-i))`

`=(-14+7i+12i-6i^2)/(5(2^2-i^2))`

`=(-14+19i-6(-1))/(5(4-(-1))`

`=(-8+19i)/(5(5)`

`=-8/25+(19i)/25`