How do you divide $(-7x^3+5x^2+2x+5)/(x-4)$ ?

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Answer 1 · 2016-07-19T22:00:13

Make the denominator appear in the numerator.

$-7x^3 + 5 x^2 - 2x + 5 = (x-4)(-7x^2 - 33x - 130) - 520 + 5$
So the division by $x-4$ yields
$-7x^2 - 33x - 130 - 515/(x-4)$

How do you divide (-7x^3+5x^2+2x+5)/(x-4) (-7x^3+5x^2+2x+5)/(x-4) ?