Question

How do you divide `( 8x^6-32x^5+4x^4 )/(x+2)`?

Answer 1

`f(x)={8x^6-32x^5+4x^4}/{x+2}={4x^4(2x^2-8x+1)}/{x+2}`

`2x-12`
`bar {2x^2-8x+1}|x+2`
`-`
`2x^2+4x`
`=`
`0x^2-12x+1`
`-`
`0x^2-12x-24`
`=`
`0x^2+0x-23`

`=>`

`f(x)=4x^4[(2x-12)-23/{x+2}]`