How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#?

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Answer 1 · 2014-11-06T16:03:20

#2xy divide {2x^2}/y#

by rewriting as a multiplication,

#=2xy cdot {y}/{2x^2}={2xy^2}/{2x^2}#

by cancelling #2x#,

#={y^2}/{x}#

I hope that this was helpful.