How do you divide and simplify \frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} 9x242x2÷21x22x81?

1 Answer
Jun 5, 2018

(3x+2)/(2(x-1)(7x+4))3x+22(x1)(7x+4)

Explanation:

"begin by factoring numerators/denominators"begin by factoring numerators/denominators

9x^2-4" is a "color(blue)"difference of squares"9x24 is a difference of squares

•color(white)(x)a^2-b^2=(a-b)(a+b)xa2b2=(ab)(a+b)

9x^2-4=(3x-2)(3x+2)9x24=(3x2)(3x+2)

2x-2=2(x-1)larr" common factor of 2"2x2=2(x1) common factor of 2

21x^2-2x-8larrcolor(blue)"factor using a-c method"21x22x8factor using a-c method

"the factors of the product "21xx-8=-168the factors of the product 21×8=168

"which sum to - 2 are - 14 and + 12"which sum to - 2 are - 14 and + 12

"split the middle term using these factors"split the middle term using these factors

21x^2-14x+12x-821x214x+12x8

=7x(3x-2)+4(3x-2)=7x(3x2)+4(3x2)

=(3x-2)(7x+4)=(3x2)(7x+4)

"the original can now be expressed as"the original can now be expressed as

((3x-2)(3x+2))/(2(x-1))-:((3x-2)(7x+4))/1(3x2)(3x+2)2(x1)÷(3x2)(7x+4)1

"to divide the 2 fractions change division to multiply"to divide the 2 fractions change division to multiply
"and turn the second fraction upside down"and turn the second fraction upside down
"cancel common factors on numerator/denominator"cancel common factors on numerator/denominator

=(cancel((3x-2))(3x+2))/(2(x-1))xx1/(cancel((3x-2))(7x+4))

=(3x+2)/(2(x-1)(7x+4))