How do you divide #(c ^ { 2} + 11c + 18) \div ( c + 9)#?

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Answer 1 · 2017-03-09T02:34:59

See the entire solution process below:

First, rewrite the expression as:

#(x^2 + 1x + 18)/(c + 9)#

Next, factor the numerator:

#((c + 9)(c + 2))/(c + 9)#

Now, cancel the common terms in the numerator and denominator:

#(color(red)(cancel(color(black)((c + 9))))(c + 2))/color(red)(cancel(color(black)(c + 9))) ->#

#c + 2# : where #c + 9 != 0# or #c != -9#