Question

How do you divide `(x^2-3) / (-6x^4+2x^2-8x+1)`?

Answer 1

`-2(3x^2+8)-{8x+47}/{-6x^4+2x^2-8x+1}`

Explanation:

`-6x^2-16`
`bar(-6x^4+2x^2-8x+1)|x^2-3`
`-`
`-6x^4-18x^2`
`bar(0x^4-16x^2-8x+1)`
`-`
`0x^4-16x^2+0x+48`
`bar(0x^4-0x^2-8x-47)`