Question

How do you divide `(x^2 + 3x +2)/(1-x)`?

Answer 1

`(x^2+3x+2)/(1-x)=-x-4+6/(1-x)`

Explanation:

by long division

Our dividend = `x^2+3x+2`
our divisor `=-x+1`

`" " " " " " " " " underline(-x-4)`
`-x+1" "|~x^2+3x+2`
`" " " " " " " " "underline(x^2-x)`
`" " " " " " " " " " " "4x+2`
`" " " " " " " " " " " "underline(4x-4)`
`" " " " " " " " " " " " " " "+6" " "larr`the remainder

so we write the answer

`("dividend")/("divisor")="quotient"+("remainder")/("divisor")`

`(x^2+3x+2)/(1-x)=-x-4+6/(1-x)`

God bless...I hope the explanation is useful ..