How do you divide (x^3-13x-18) / (x-4) ?

1 Answer
Aug 8, 2017

x^2+4x+3-6/(x-4)

Explanation:

"one way is to use the divisor as a factor in the numerator"

"consider the numerator"

color(red)(x^2)(x-4)color(magenta)(+4x^2)-13x-18

=color(red)(x^2)(x-4)color(red)(+4x)(x-4)color(magenta)(+16x)-13x-18

=color(red)(x^2)(x-4)color(red)(+4x)(x-4)color(red)(+3)(x-4)color(magenta)(+12)-18

=color(red)(x^2)(x-4)color(red)(+4x)(x-4)color(red)(+3)(x-4)-6

"quotient "=color(red)(x^2+4x+3)," remainder "=-6

rArr(x^3-13x-18)/(x-4)=x^2+4x+3-6/(x-4)