How do you divide $\frac{- x^{3} - 3 x^{2} + 7 x + 5}{x - 5}$ $(-x^3-3x^2+7x+5)/(x-5)$ ?

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How do you divide $\frac{- x^{3} - 3 x^{2} + 7 x + 5}{x - 5}$ $(-x^3-3x^2+7x+5)/(x-5)$ ?

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Answer 1 · 2017-07-13T16:10:30

see below

Explanation:

to divide $\frac{- x^{3} - 3 x^{2} + 7 x + 5}{x - 5}$ $(−x^3−3x^2+7x+5)/(x−5)$ , use long division

$(x - 5)$ $(x−5)$ l $(- x^{3} - 3 x^{2} + 7 x + 5)$ $(−x^3−3x^2+7x+5)$ (l is supposed to be the long dividion symbol

$- 1 x^{2} - 8 x - 33 r - \frac{160}{x - 5}$ $" "-1x^2 -8x -33 r-160/(x-5)$
$(x - 5)$ $(x−5)$ l $(- x^{3} - 3 x^{2} + 7 x + 5)$ $(−x^3−3x^2+7x+5)$
$- x^{3} + 5 x^{2}$ $" "-x^3+5x^2$
subtract
$- 8 x^{2} + 7 x + 5$ $" " -8x^2+7x+5$
$- 8 x^{2} + 40 x$ $" "-8x^2+40x$
subtract
$- 33 x + 5$ $" "-33x+5$
$- 33 x + 165$ $" "-33x+165$
subtract
$- 160$ $" "-160$

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How do you divide $\frac{- x^{3} - 3 x^{2} + 7 x + 5}{x - 5}$ $(-x^3-3x^2+7x+5)/(x-5)$ ?

1 Answer

Explanation:

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How do you divide −x3−3x2+7x+5x−5(-x^3-3x^2+7x+5)/(x-5) ?

1 Answer

Explanation:

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How do you divide $\frac{- x^{3} - 3 x^{2} + 7 x + 5}{x - 5}$ $(-x^3-3x^2+7x+5)/(x-5)$ ?