Question

How do you divide `( x^3+4x^2+x-6 )/(x-3)`?

Answer 1

`((x^2+1)(x+4)(x-6))/(x-3)`

Explanation:

Assuming that you mean simplifying:

`(x^3+4x^2+x-6)/(x-3)`

`=(x^2(x+4)+1(x-6))/(x-3)`

`=((x^2+1)(x+4)(x-6))/(x-3)`, `x!=3`