How do you divide $(x^{3} - 6 x - 25 x - 18) \div (x + 2)$ $(x^3-6x-25x-18)÷(x+2)$ ?

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Answer 1 · 2015-10-11T05:57:34

Remainder: $48$ $48$

Use the Factor Theorem which states that:

If $x - a$ $x-a$ is a factor of the polynomial $f (x) \Rightarrow f (a) = 0$ $f(x) rArr f(a)=0$

Take $(x + 2) = 0$ $(x+2)=0$ so $x = - 2$ $x=-2$ .

$f (- 2) = {(- 2)}^{3} - 6 (- 2) - 25 (- 2) - 18$ $f(-2)=(-2)^3-6(-2)-25(-2)-18$

$= 48$ $=48$

Hence $48$ $48$ is your remainder.

How do you divide (x^3-6x-25x-18)÷(x+2)(x3−6x−25x−18)÷(x+2)(x^3-6x-25x-18)÷(x+2)?