How do you divide #(x^3-7x-6) / (x+1) #?

Question

How do you divide #(x^3-7x-6) / (x+1) #?

↳Redirected from "How do you calculate the oxidation number of an element in a compound?"

1 Answer

Impact of this question

3701 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-16T03:25:59

#(x^2(x+1)-x^2-7x-6)/(x+1)#
#=(x^2(x+1)-x(x+1)-6x-6)/(x+1)#
#=(x^2(x+1)-x(x+1)-6(x+1))/(x+1)#
#=(x^2(x+1))/(x+1)-(x(x+1))/(x+1)-(6(x+1))/(x+1)#
#=x^2-x-6#

Science

Math

Humanities

... and beyond

How do you divide #(x^3-7x-6) / (x+1) #?

1 Answer

Related questions

Impact of this question