Question

How do you divide `(x^3 - 7x - 6)/(x+1)`?

Answer 1

Quotient is `x^2-x-6` and remainder is `0`

Explanation:

`x^3-7x-6`

=`x^3+x^2-x^2-x-6x-6`

=`x^2*(x+1)-x*(x+1)-6*(x+1)`

=`(x^2-x-6)*(x+1)`

Hence quotient is `x^2-x-6` and remainder is `0`