How do you divide $(x^3-8x^2-6) / (x-2)$ ?

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Answer 1 · 2018-06-24T12:07:30

The quotient is $=x^2-6x-12$ and the remainder is $-30$

Perform a long division

$color(white)(aaaa)$ $x^3-8x^2+0x-6$ $color(white)(aaaa)$ $|$ $x-2$

$color(white)(aaaa)$ $x^3-2x^2$ $color(white)(aaaaaaaaaaaa)$ $|$ $x^2-6x-12$

$color(white)(aaaa)$ $0-6x^2+0x$

$color(white)(aaaaaa)$ $-6x^2+12x$

$color(white)(aaaaaaaaa)$ $0-12x-6$

$color(white)(aaaaaaaaaaa)$ $-12x+24$

$color(white)(aaaaaaaaaaaaaaa)$ $0-30$

The quotient is $=x^2-6x-12$ and the remainder is $-30$

$(x^3-8x^2-6)/(x-2)=x^2-6x-12-30/(x-2)$

How do you divide (x^3-8x^2-6) / (x-2)(x^3-8x^2-6) / (x-2)?