How do you divide $\frac{x^{3} - x^{2} + 1}{x - 1}$ $(x^3 -x^2+1 )/ (x - 1)$ ?

Question

2021 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-19T11:04:29

$\frac{x^{3} - x^{2} + 1}{x - 1} = x^{2} + \frac{1}{x - 1}$ $(x^3-x^2+1)/(x-1) = x^2+1/(x-1)$

$(x^3-x^2+1)/(x-1) = (x^2(x-1)+1)/(x-1) = (x^2color(red)(cancel(color(black)((x-1)))))/color(red)(cancel(color(black)((x-1))))+1/(x-1) = x^2+1/(x-1)$

How do you divide (x^3 -x^2+1 )/ (x - 1)x3−x2+1x−1(x^3 -x^2+1 )/ (x - 1)?