How do you divide −x3−x2−6x+5(−x+10)?

1 Answer
Shwetank Mauria
Feb 21, 2016

−x3−x2−6x+5−x+10 is

x2+11x+116−1155−x+10

Explanation:

To divide −x3−x2−6x+5 by −x+10, first we observe that −x goes −x3−x=x2 times in −x3.

Hence, x2(−x+10)−10x2−x2−6x+5 or
(note we have added and subtracted 10x2)x^2(-x+10)-11x^2−6x+5#

As −11x2−x=11x, above can be written is

x2(−x+10)+11x(−x+10)−110x−6x+5 or

x2(−x+10)+11x(−x+10)−116x+5

and as −116x−x=116, above can be written as

x2(−x+10)+11x(−x+10)+116x(−x+10)−1160+5 or

x2(−x+10)+11x(−x+10)+116x(−x+10)−1155 or

(x2+11x+116)(−x+10)−1155 or

Hence −x3−x2−6x+5−x+10 is

x2+11x+116−1155−x+10

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