How do you divide x4+6x3+8x+12x23x+9?

1 Answer
May 17, 2016

Dividing x4+6x3+8x+12 by x23x+9,

the quotient is x2+3x+18 and remainder is 35x150

Explanation:

To divide x4+6x3+8x+12 by x23x+9,

as x4x2=x2.

Now x2×(x23x+9)=x4+3x39x2

Subtracting x4+3x39x2 from x4+6x3+8x+12, we get

(x4+6x3+8x+12)(x4+3x39x2)=3x3+9x2+8x+12

Now in similar way 3x3+9x2+8x+12, x23x+9 can go 3x times and remainder will be

3x3+9x2+8x+123x(x23x+9)

= 3x3+9x2+8x+123x3+9x227x

= 18x219x+12

Now in this, x23x+9 goes 18 times and remainder is

18x219x+1218(x23x+9)=19x+54x+12162=35x150

Hence when we divide x4+6x3+8x+12 by x23x+9, the quotient is x2+3x+18 and remainder is 35x150