How do you divide $\frac{- x^{4} + 6 x^{3} + 8 x + 12}{x^{2} - 5 x + 2}$ $(-x^4+6x^3+8x+12)/(x^2-5x+2)$ ?

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How do you divide $\frac{- x^{4} + 6 x^{3} + 8 x + 12}{x^{2} - 5 x + 2}$ $(-x^4+6x^3+8x+12)/(x^2-5x+2)$ ?

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Answer 1 · 2018-01-06T10:31:49

$- x^{2} + x + 7 + \frac{41 x - 2}{x^{2} - 5 x + 2}$ $-x^2+x+7+(41x-2)/(x^2-5x+2)$

Explanation:

Using place keepers. For example: $0 x^{2}$ $0x^2$

$ddddddddddddddddd - x^{4} + 6 x^{3} + 0 x^{2} + 8 x + 12$ $color(white)("ddddddddddddddddd")-x^4+6x^3+0x^2+8x+12$
$color(magenta)(-x^2)(x^2-5x+2)-> ul(-x^4+5x^3-2x^2 larr" Subtract"$
$color(white)("dddddddddddddddddddd")0+ color(white)("d")x^3+2x^2+8x+12$
$color(magenta)(+x)(x^2-5x+2)-> color(white)("ddddd")ul(+color(white)("d")x^3-5x^2+2x larr" Subtract")$
$color(white)("ddddddddddddddddddddddd")0 color(white)("d")+ color(white)(".")7x^2 +color(white)("d")6x+12$
$color(magenta)(+7)(x^2-5x+2)-> color(white)("dd..dddddd")ul( +color(white)("d")7x^2-35x+14 larr" Sub.")$
$color(magenta)("Remainder "-> color(white)("ddddddddddddddddd") 0 color(white)("d")+41x-2)$

$color(magenta)( -x^2+x+7+(41x-2)/(x^2-5x+2) )$

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How do you divide $\frac{- x^{4} + 6 x^{3} + 8 x + 12}{x^{2} - 5 x + 2}$ $(-x^4+6x^3+8x+12)/(x^2-5x+2)$ ?

1 Answer

Explanation:

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How do you divide (-x^4+6x^3+8x+12)/(x^2-5x+2)−x4+6x3+8x+12x2−5x+2(-x^4+6x^3+8x+12)/(x^2-5x+2)?

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Explanation:

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How do you divide $\frac{- x^{4} + 6 x^{3} + 8 x + 12}{x^{2} - 5 x + 2}$ $(-x^4+6x^3+8x+12)/(x^2-5x+2)$ ?