How do you divide x4−9x2−2x2+3x−1?

1 Answer
George C.
Jun 29, 2018

x4−9x2−2x2+3x−1=x2−3x+1−6x+1x2+3x−1

Explanation:

One method involves separating out multiples of the denominator from the numerator, starting with the highest degree term. This is equivalent to polynomial long division.

We find:

x4−9x2−2x2+3x−1

=(x4+3x3−x2)−3x3−8x2−2x2+3x−1

=x2(x2+3x−1)−(3x3+8x2+2)x2+3x−1

=x2−3x3+8x2+2x2+3x−1

=x2−(3x3+9x2−3x)−x2+3x+2x2+3x−1

=x2−3x(x2+3x−1)−(x2−3x−2)x2+3x−1

=x2−3x+x2−3x−2x2+3x−1

=x2−3x+(x2+3x−1)−6x−1x2+3x−1

=x2−3x+1−6x+1x2+3x−1

Related questions
See all questions in Division of Polynomials
Impact of this question
1741 views around the world
You can reuse this answer
Creative Commons License