Question

How do you evaluate `18^(x-2) = 13^(-2x)`?

Answer 1

`x = (2 log(18))/(2 log(13) + log(18))`

Explanation:

Applying `log` to each equation side
`(x-2)log(18)=-2x log(13)`
solving for `x` gives
`x = (2 log(18))/(2 log(13) + log(18))`