How do you evaluate $18^(x-2) = 13^(-2x)$ ?

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Answer 1 · 2016-05-15T14:09:46

$x = (2 log(18))/(2 log(13) + log(18))$

Applying $log$ to each equation side
$(x-2)log(18)=-2x log(13)$
solving for $x$ gives
$x = (2 log(18))/(2 log(13) + log(18))$

How do you evaluate 18^(x-2) = 13^(-2x)18^(x-2) = 13^(-2x)?