How do you evaluate #2(a-b)^2-5c# given a=12, b=9, c=4?

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Answer 1 · 2016-10-02T14:53:38

The answer is #-2#

#2(color(red)a-color(blue)b)^2-5color(violet)c color(white)(aaa)# given #a=color(red)(12), b=color(blue)9, c=color(violet) 4 #

Substitute #color(red)(12)# for #color(red)a#, #color(blue)9# for #color(blue)b#, and #color(violet)4# for #color(violet)c#.

#2(color(red)(12)-color(blue)9)^2-5(color(violet)4)#

#2(color(white)(aa)3color(white)(aaa))^2-20#

#2(9)-20#

#18-20#

#-2#