How do you evaluate $2 {(a - b)}^{2} - 5 c$ $2(a-b)^2-5c$ given a=12, b=9, c=4?

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How do you evaluate $2 {(a - b)}^{2} - 5 c$ $2(a-b)^2-5c$ given a=12, b=9, c=4?

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Answer 1 · 2016-10-02T14:53:38

The answer is $- 2$ $-2$

Explanation:

$2 {(a - b)}^{2} - 5 c a a a$ $2(color(red)a-color(blue)b)^2-5color(violet)c color(white)(aaa)$ given $a = 12, b = 9, c = 4$ $a=color(red)(12), b=color(blue)9, c=color(violet) 4$

Substitute $12$ $color(red)(12)$ for $a$ $color(red)a$ , $9$ $color(blue)9$ for $b$ $color(blue)b$ , and $4$ $color(violet)4$ for $c$ $color(violet)c$ .

$2 {(12 - 9)}^{2} - 5 (4)$ $2(color(red)(12)-color(blue)9)^2-5(color(violet)4)$

$2 {(a a 3 a a a)}^{2} - 20$ $2(color(white)(aa)3color(white)(aaa))^2-20$

$2 (9) - 20$ $2(9)-20$

$18 - 20$ $18-20$

$- 2$ $-2$

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How do you evaluate $2 {(a - b)}^{2} - 5 c$ $2(a-b)^2-5c$ given a=12, b=9, c=4?

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Explanation:

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How do you evaluate $2 {(a - b)}^{2} - 5 c$ $2(a-b)^2-5c$ given a=12, b=9, c=4?