How do you evaluate $\frac{3}{4} + \frac{1}{3} + \frac{1}{2}$ $3/4 + 1/3 + 1/2$ ?

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How do you evaluate $\frac{3}{4} + \frac{1}{3} + \frac{1}{2}$ $3/4 + 1/3 + 1/2$ ?

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Answer 1 · 2018-06-06T20:02:43

$\Rightarrow \frac{19}{12}$ $=>19/12$

Explanation:

The fractions need to be expressed with a common denominator. There a few ways to obtain one, the easiest being to multiply all denominators together and multiplying each fraction by some expression equivalent to $1$ $1$ , as this prevents the expression from changing.

$\frac{3}{4} + \frac{1}{3} + \frac{1}{2}$ $3/4 + 1/3 + 1/2$

$= \frac{3}{4} \cdot \frac{3}{3} \cdot \frac{2}{2} + \frac{1}{3} \cdot \frac{4}{4} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{4}{4} \cdot \frac{3}{3}$ $=3/4*3/3*2/2 + 1/3*4/4*2/2 + 1/2*4/4*3/3$

$= \frac{18}{24} + \frac{8}{24} + \frac{12}{24}$ $=18/24 + 8/24 + 12/24$

$= \frac{38}{24}$ $= 38/24$

$= \frac{19}{12}$ $=19/12$

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