How do you evaluate $3 y (x + x^{2} - y)$ $3y(x+x^2-y)$ given x=-2, y=-3, z=5?

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Answer 1 · 2016-10-30T19:27:00

$- 45$ $-45$

$3 y (x + x^{2} - y)$ $3y(x+x^2-y)$

Well you would put in the given values for x and y.

So $- 2$ $-2$ would go in for where each $x$ $x$ is and

$- 3$ $-3$ would go in for $y$ $y$ making the expression:

$3 (- 3) [- 2 + {(- 2)}^{2} - (- 3))]$ $3(-3)[-2+(-2)^2-(-3))]$ I am not sure where z fits in but it may just be extra..

= $- 9 [- 2 + 4 + 3]$ $-9[-2+4+3]$

= $- 9 \times 5$ $-9 xx 5$

= $- 45$ $-45$

How do you evaluate 3y(x+x^2-y)3y(x+x2−y)3y(x+x^2-y) given x=-2, y=-3, z=5?