How do you evaluate #7/4-(-1/2)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Barney V. Mar 8, 2018 #9/4# or2 1/4# Explanation: #7/4-(-1/2)# #:.=7/4+1/2# #:.=(7+2)/4# #:.=9/4# or #2 1/4# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 3729 views around the world You can reuse this answer Creative Commons License