How do you evaluate $8 e^{3 x + 4} = 15$ $8e^(3x+4)=15$ ?

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Answer 1 · 2016-04-21T17:05:31

$x = \frac{ln (\frac{15}{8}) - 4}{3}$ $x=(ln(15/8)-4)/3$

$e^{3 x + 4} = \frac{15}{8}$ $e^(3x+4)=15/8$

${ln e}^{3 x + 4} = ln (\frac{15}{8})$ $ln e^(3x+4)=ln(15/8)$

$(3 x + 4) ln e = ln (\frac{15}{8})$ $(3x+4) lne=ln(15/8)$

$(3 x + 4) = ln (\frac{15}{8})$ $(3x+4)=ln(15/8)$

$3 x = ln (\frac{15}{8}) - 4$ $3x=ln(15/8)-4$

$x = \frac{ln (\frac{15}{8}) - 4}{3}$ $x=(ln(15/8)-4)/3$

How do you evaluate 8e3x+4=158e^(3x+4)=15?