How do you evaluate $(a^{2} \div 4 b) + c$ $(a^2div4b)+c$ given a=12, b=9, c=4?

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How do you evaluate $(a^{2} \div 4 b) + c$ $(a^2div4b)+c$ given a=12, b=9, c=4?

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Answer 1 · 2017-04-14T13:14:57

$8$ $8$

Explanation:

$a^{2} \div 4 b + c = \frac{a^{2}}{4 b} + c$ $a^2-:4b+c=a^2/(4b)+c$

$Substitute the given values into the expression$ $"Substitute the given values into the expression"$

$\Rightarrow \frac{{(12)}^{2}}{4 \times 9} + 4$ $rArr(12)^2/(4xx9)+4$

$= \frac{144}{36} + 4$ $=144/36+4$

$= 4 + 4$ $=4+4$

$= 8$ $=8$

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How do you evaluate $(a^{2} \div 4 b) + c$ $(a^2div4b)+c$ given a=12, b=9, c=4?

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Explanation:

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How do you evaluate (a2÷4b)+c(a^2div4b)+c given a=12, b=9, c=4?

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How do you evaluate $(a^{2} \div 4 b) + c$ $(a^2div4b)+c$ given a=12, b=9, c=4?