Question

How do you evaluate `[(a-b)*c]2*d` given a=25, b=14, c=3, d=7?

Answer 1

`924`

Explanation:

`[(a-b)xxc]2xxd, a=25, b=14, c=3, d=7`

To evaluate, we need to replace the letters with numbers and then perform the operation.

First, we have to subtract `a` from `b`. This will give us `11`.

`[(25-14)xx3]2xx14 = (11xx3)2xx14`

Then we must perform the multiplications. It doesn't matter which order we perform these in, as multiplication is commutative `(axxbxxc=axxcxxb=cxxbxxa)`.

`11xx3xx2xx14=924`