How do you evaluate $b^{2} + 2 a - c^{2}$ $b^2+2a-c^2$ given a=12, b=9, c=4?

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How do you evaluate $b^{2} + 2 a - c^{2}$ $b^2+2a-c^2$ given a=12, b=9, c=4?

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Answer 1 · 2018-04-24T04:03:26

$9^{2} + 2 (12) - 4^{2} = 89$ $9^2 + 2(12) - 4^2 = 89$

Explanation:

$a = 12, b = 9, c = 4$ $a=12, b=9, c=4$

$b^{2} + 2 a - c^{2}$ $b^2 +2a - c^2$

$= 9^{2} + 2 (12) - 4^{2}$ $= 9^2 + 2(12) - 4^2$

$= 81 + 24 - 16$ $= 81 + 24 - 16$

$= 89$ $= 89$

Answer 2 · 2018-04-24T04:05:42

89

Explanation:

$b^{2} + 2 a - c^{2}$ $b^2+2a-c^2$
so here $b = 9, c = 4, a = 12 (g i v e n)$ $b=9,c=4,a=12(given)$
substituting the values,
${(9)}^{2} + 2 (12) - {(4)}^{2}$ $(9)^2+2(12)-(4)^2$
(HOPE YOU NOW ${(9)}^{2} = 81$ $(9)^2=81$ AND ${(4)}^{2} = 16$ $(4)^2=16$ )
$= 81 + 24 - 16$ $=81+24-16$ $= 105 - 16$ $=105-16$
$= 89$ $=89$
SO THE ANSWER HERE IS
$89$ $89$

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2 Answers

Explanation:

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