How do you evaluate $b^{2} - 4 a c$ $b^2-4ac$ for a=-1, b=-5, and c=2?

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Answer 1 · 2018-07-09T22:18:05

$33$ $33$

$b^{2} - 4 a c$ $b^2 - 4ac$ for $a = - 1$ $a = -1$ , $b = - 5$ $b = -5$ , and $c = 2$ $c = 2$

To evaluate the expression, plug in the given values for each variable:
${(- 5)}^{2} - 4 (- 1) (2)$ $(-5)^2 - 4(-1)(2)$

Simplify:
$= 25 - 4 (- 2)$ $=25 - 4(-2)$

$= 25 + 8$ $=25+8$

$= 33$ $=33$

Hope this helps!

How do you evaluate b2−4acb^2-4ac for a=-1, b=-5, and c=2?