How do you evaluate $\frac{b c^{2} + a}{c}$ $(bc^2+a)/c$ given a=12, b=9, c=4?

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Answer 1 · 2018-03-27T22:57:01

See a solution process below:

Substitute:

$\frac{b c^{2} + a}{c}$ $(color(blue)(b)color(green)(c)^2 + color(red)(a))/color(green)(c)$ becomes:

$\frac{(9 \times 4^{2}) + 12}{4} \Rightarrow$ $((color(blue)(9) xx color(green)(4)^2) + color(red)(12))/color(green)(4) =>$

$\frac{(9 \times 16) + 12}{4} \Rightarrow$ $((color(blue)(9) xx color(green)(16)) + color(red)(12))/color(green)(4) =>$

$\frac{144 + 12}{4} \Rightarrow$ $(144 + color(red)(12))/color(green)(4) =>$

$\frac{156}{4} \Rightarrow$ $156/color(green)(4) =>$

$39$ $39$

How do you evaluate bc2+ac(bc^2+a)/c given a=12, b=9, c=4?