How do you evaluate #f(0)# given the function #f(x)=\frac{5(2-x)}{11}#? Algebra Graphs of Linear Equations and Functions Function Notation and Linear Functions 1 Answer Wataru Dec 10, 2014 By replacing #x# by #0#, we have #f(0)={5(2-0)}/{11}=10/11# I hope that this was helpful. Answer link Related questions What is an example of a linear equation written in function notation? What is a function? How do you evaluate #f(4)# given the function #f(x)=2x-6#? How do you evaluate #g(-1)# given the function #g(t)=-5t+1#? How do you write linear equations in function notation? How do you rewrite #9x+3y=6# in function notation? How do you evaluate #f(p)# given the function #f(x)=6x-36#? What are linear functions? How do you evaluate #f(-1)# given the function #f(t)=\frac{1}{2} t^2+4#? How do you evaluate #f(x+1)# given the function #f(x)=3-\frac{1}{2} x#? See all questions in Function Notation and Linear Functions Impact of this question 8596 views around the world You can reuse this answer Creative Commons License