How do you rewrite #9x+3y=6# in function notation?

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Answer 1 · 2014-12-08T01:01:12

By solving for #y#.

#9x+3y=6#

Subtract #9x# from both sides.

#9x+3y-9x=6-9x#

Simplify

#3y=-9x+6#

Divide by 3

#(3y)/3=-(9x)/3+6/3#

So...

#y=-3x+2#

since #y# can be replaced with #f(x)#, then your final answer is

#f(x)=-3x+2#