Question

How do you evaluate `ln (2x+3)=7`?

Answer 1

`x~~546.817` or `x=(e^7 -3)/2`

Explanation:

Remember, anytime you see ln, it is always equal to
`loge` (the e is a subscript). You work with them the same way as you would any other log.
Problem:
`ln(2x+3)=7`
Step 1: take `loge` of both sides.
`ln(2x+3)=ln(e^7)`
Step 2: Since the logs have the same bases, make the `(2x+3)=(e^7)` equal to each other
Step 3: Solve so the x is on the left side by itself:
`x=(e^7 -3)/2`
Step 4: if you need the decimal form, just plug in 2.718281828 (Euler's number) for e and solve.
#x=(2.718281828 ^7 -3)/2 => x~~546.817#