How do you evaluate $Log_(1050) (1+x)=137$ ?

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Answer 1 · 2018-05-10T17:44:16

...the base seems very big...but anyway:

We can use the definition of log to write it as an exponential getting rid of the log as:

$x+1=1050^(137)$

and:

$x=1050^(137)-1$

that is a BIG number!!!

(something like $8xx10^(413)$ !!!!)

How do you evaluate Log_(1050) (1+x)=137Log_(1050) (1+x)=137?