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How do you evaluate ${log}_{64} (1)$ $log_64(1)$ ?

1 Answer

Nov 15, 2015

${log}_{64} 1 = 0$ $log_64 1 = 0$

Explanation:

${log}_{a} 1 = 0$ $log_a 1 = 0$ for any base $a$ $a$

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