How do you evaluate #Sin^2 (pi/9) + Cos^2( pi/9)#?

1 Answer
Feb 4, 2016

#1#

Explanation:

Without even considering the arguments of sine and cosine, there is an identity that for all #x#, #sin^2(x) + cos^2(x) = 1#.

One way of seeing that this is true is to consider the unit circle, and note that for any point on the circle with angle #theta#, #cos(theta)# is the #x#-coordinate of that point, and #sin(theta)# is the #y#-coordinate. Then, drawing a right triangle with the hypotenuse connecting the origin and the point, we find that the triangle has legs of length #cos(theta)# and #sin(theta)#, and a hypotenuse of length #1#. Applying the Pythagorean theorem gives us the desired result.