How do you solve #\sqrt { ( x - 2) ( x + 4) } - x - 2= 0#?
2 Answers
No solutions
Explanation:
writing
by squaring we get
or
This fulfilles not our equation since
Move values that are not under the radical to the other side and square both sides. After Rearranging, you will find
Explanation:
First, move the values that aren't under the radical to the Right Hand Side (RHS):
Next, we'll FOIL the two expressions that are under the radical:
Next, we'll square both sides to get rid of the radical:
We can eliminate the
Finally, divide both sides by
Let's apply this back in the (somewhat) original equation:
Now, here's a tricky part. The square root of a number can be either positive or negative, since any real number squared is ALWAYS positive.