How do you evaluate the definite integral #int 4/sin^2(z) dz# from #[pi/6, pi/2]#? Calculus Introduction to Integration Formal Definition of the Definite Integral 1 Answer Ratnaker Mehta · mason m Sep 2, 2016 #4sqrt3#. Explanation: #int_(pi/6)^(pi/2) 4/sin^2 zdz=4int_(pi/6)^(pi/2)csc^2 zdz# #=-4[cot z]_(pi/6)^(pi/2)# #=-4[cot (pi/2)-cot (pi/6)]# #=-4[0-sqrt3]# #=4sqrt3#. Answer link Related questions What is the Formal Definition of the Definite Integral of the function #y=f(x)# over the... How do you use the definition of the definite integral? What is the integral of dy/dx? What is an improper integral? How do you calculate the double integral of #(xcos(x+y))dr# where r is the region: 0 less than... How do you apply the evaluation theorem to evaluate the integral #3t dt# over the interval [0,3]? What is the difference between an antiderivative and an integral? How do you integrate #3x^2-5x+9# from 0 to 7? Question #f27d5 How do you evaluate the definite integral #int sqrtt ln(t)dt# from 2 to 1? See all questions in Formal Definition of the Definite Integral Impact of this question 1696 views around the world You can reuse this answer Creative Commons License