How do you evaluate the expression $\frac{10 - y}{14 - x}$ $(10-y)/(14-x)$ when x=6 and y=8?

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Answer 1 · 2017-02-09T10:49:15

$\frac{1}{4}$ $1/4$

$\frac{10 - y}{14 - x}$ $(10-y)/(14-x)$ , when $x = 6$ $x=6$ and $y = 8$ $y=8$

Substitute $6$ $6$ for $x$ $x$ and $8$ $8$ for $y$ $y$ .

$\frac{10 - 8}{14 - 6}$ $(10-8)/(14-6)$

Simplify.

$\frac{2}{8} = \frac{1}{4}$ $2/8=1/4$

How do you evaluate the expression 10−y14−x(10-y)/(14-x) when x=6 and y=8?